motor sprocket
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Re: motor sprocket
1 tooth on trans is equal to 3 on motor
Not even close, how is three times 16 equal to 28?
The math already done on my site: http://www.victorylibrary.com/tech/gr-45.htm
You won't be able to pull 5,000 in high gear without serious engine work, but 4,000 is fairly easy (multiply the speed shown by 80%).
Not even close, how is three times 16 equal to 28?
The math already done on my site: http://www.victorylibrary.com/tech/gr-45.htm
You won't be able to pull 5,000 in high gear without serious engine work, but 4,000 is fairly easy (multiply the speed shown by 80%).
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Re: motor sprocket
Do the math? Thinking of trying some different wheel and tire sizes so may need to do some more figures. Hope to end up with tires with same diameter as 5.00-16. So what is the formula for the over all ratio? May need to come up with different sprocket combo to make it work out like I want. 16 in donut spares with 4-1/2 in bolt center may do the trick. Anyone try that? Thanks for all your help.
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Re: motor sprocket
Final drive ratio = clutch sprocket × axle sprocket ÷ engine sprocket ÷ transmission sprocket (if belt, substitute pulley teeth, duh)
59 × 37 ÷ 30 ÷ 17 = 4.28:1
Ratio in intermediate gear: above calculation × actual ratio
4.28 × 1.57:1 (45 2nd gear) = 6.72:1
MPH = tire OD × RPM × .00295 ÷ final drive ratio
26" × 4,000 × .00295 ÷ 4.28 = 71.68 mph
There are 10 others, and they all do the same thing. For most bikes, 26" is almost assumed.
A 16" donut is very likely a low profile (aspect ratio) and will not be 26" tall even if 5.00" section width.
59 × 37 ÷ 30 ÷ 17 = 4.28:1
Ratio in intermediate gear: above calculation × actual ratio
4.28 × 1.57:1 (45 2nd gear) = 6.72:1
MPH = tire OD × RPM × .00295 ÷ final drive ratio
26" × 4,000 × .00295 ÷ 4.28 = 71.68 mph
There are 10 others, and they all do the same thing. For most bikes, 26" is almost assumed.
A 16" donut is very likely a low profile (aspect ratio) and will not be 26" tall even if 5.00" section width.